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A body of mass 4 kg weighs 4.8 kg when suspended in a moving lift. the accelereation of the lift is
Just use the concept of pseudo force for the body inside lift .
Let lift moves upward wiz acc. A so for body in FBD equ. Will be m(gplus a) = 4.8. Solve it for a . Acc. Of lift will come out to be 8.6 m/s downwards
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