A man weighing 80Kg is standing on a trolley weighing 320Kg. The trolley is resting on a frictionless surface. If the man starts walking on the trolley along its length at speed 1 m/s, then his relative displacement with respect to ground after 4s is_______

Dear sindhu

 

let initial c.o.m of trolley and man  from y axis is a and b repectivily

Xc.m=(320*a +80*b)/400

at final position after 4 sec =Xc.m ={320*(a-x1) +80*(b+4-x1)}/400

so equate

{320*(a-x1) +80*(b+4-x1)}/400  =(320*a +80*b)/400

-400x1 +320 =0

x1=4/5

 

so 4-x1=4-4/5 =16/5

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