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a car is travelling on a straight road.The max. velocity the car can attain is 24ms-1.the max. acc. and dece. it can attain is 1ms-2 and 4ms-2 respectively.The shortest time the car takes from rest to rest in a distance of 200m is....???

Murtaza Khanjiwala , 12 Years ago
Grade
anser 2 Answers
mahendra shah

distance = (A)(B)(t^2) / 2(A+B) ..

where A is acceleration  , B is reatardation and t is the time taken..

since t is unknown..

formula for max. velocity = ABt/(A+B) ..

we get t = 30s

therefore putting it in distane formula ..

we get s = 360 m..

Last Activity: 12 Years ago
Murtaza Khanjiwala

its wrong ans. is 22.4 s

its dc pandey sum

Last Activity: 12 Years ago
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