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a car is travelling on a straight road.The max. velocity the car can attain is 24ms-1.the max. acc. and dece. it can attain is 1ms-2 and 4ms-2 respectively.The shortest time the car takes from rest to rest in a distance of 200m is....???
distance = (A)(B)(t^2) / 2(A+B) ..
where A is acceleration , B is reatardation and t is the time taken..
since t is unknown..
formula for max. velocity = ABt/(A+B) ..
we get t = 30s
therefore putting it in distane formula ..
we get s = 360 m..
its wrong ans. is 22.4 s
its dc pandey sum
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