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Grade Upto college levelMechanics

the position of a particle along a straight line is given by s=t^3-9t^2-15t here t is in seconds determine its maximum accleration during the time 0<=t<=10s

Profile image of akash kashyp
16 Years agoGrade Upto college level
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Profile image of Badiuddin askIITians.ismu Expert
16 Years ago

Dear akash

s=t3-9t2-15t

v=ds/dt =3t2-18t-15

a=dv/dt =6t-18

maximum acelaation occure at t=10 sec

amax=6*10-18

        =42


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