# A particle is projected vertically upward with a velocity V0 ,but due to horizontal wind the particle experiences a horizontal constant accleration of a0 m/s2 . The horizontal distance travelled by the particle in a time interval in which its velocity vector rotates by 900 is_____________.

148 Points
13 years ago

Dear sindhuja

Initial velocity vector =V0 j

when particle will be at max hight then it has no verticle velocity,it has velocity in the horizontal direction only.

final velocity vector =V1 i

and this will be the position where velocity vector rotates by 90 degree.

so time taken to reach highest point is

0=V0 -gt

t=V0/g

and in this time horizontal distance travelled

S=0 + 1/2 *a0*(V0/g)2

S=a0V02/2g2

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Shane Macguire
30 Points
13 years ago