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A particle is projected vertically upward with a velocity V0 ,but due to horizontal wind the particle experiences a horizontal constant accleration of a0 m/s2 . The horizontal distance travelled by the particle in a time interval in which its velocity vector rotates by 900 is_____________.
Dear sindhuja
Initial velocity vector =V0 j
when particle will be at max hight then it has no verticle velocity,it has velocity in the horizontal direction only.
final velocity vector =V1 i
and this will be the position where velocity vector rotates by 90 degree.
so time taken to reach highest point is
0=V0 -gt
t=V0/g
and in this time horizontal distance travelled
S=0 + 1/2 *a0*(V0/g)2
S=a0V02/2g2
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