A bullet is fired from a gun. The force on the bullet is given by f= 600-[2*10^5]t. The force on bullet become zero as given by equation as soon as it leaves the barrel. The impulse imparted is?

600 N

first we shall find the time taken by the bullet to come out of te barrel.

this will help us calculate the impulse on the bullet

the required time is 3*10^-3 s.

now we can calculate the impulse by two ways.

the first way is integration which is the most common method.

J = ∫F(t)dt = ∫{600-(2*10⁵t)}dt 

 the limits shall be from t = 0 to t = 3*10^-3 s.

the other way is very simple. it is the method of average.

when a quantity has a linear variation we can take the average of the initial and final quantiites to evaluate such an integral

that is if F is a linear function of t then

∫₀^TF(t)dt = <F(t)>T = {F(t = 0) + F(t = T)}/2.

both these ways give the same answer as 300 N-s.