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A balloon starts rising from ground,vertically upwards,uniformly at rate of 1m/s.At end of 4sec a body was released from balloon.Calculate the time taken by released body to reach ground?

reshma lr , 11 Years ago
Grade 11
anser 5 Answers
abcd abcd

Last Activity: 11 Years ago

1 second

Nimisha roy

Last Activity: 11 Years ago

0.27?

Saurabh Anand

Last Activity: 11 Years ago

initial velocity of the body will be equal to the velocity of balloon i.e. 1m/s in upward direction....and thus calculate...the answer will be 1 sec....0.1s in going up and 0.9s in coming down....

vivek kumar

Last Activity: 11 Years ago

1s

SOURAV MISHRA

Last Activity: 11 Years ago

the velocity of the released body is 1m/s upwards.

and its acceleration will be 10m/s2 downwards.

when released it was at a height of 4m from the ground.

so the equation is 5t2 - t - 4 = 0.

this gives t = 1s.

the body will take 1s to reach the ground.

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