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Grade 11Mechanics

A balloon starts rising from ground,vertically upwards,uniformly at rate of 1m/s.At end of 4sec a body was released from balloon.Calculate the time taken by released body to reach ground?

Profile image of reshma lr
13 Years agoGrade 11
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5 Answers

Profile image of abcd abcd
13 Years ago

1 second

Profile image of Nimisha roy
13 Years ago

0.27?

Profile image of Saurabh Anand
13 Years ago

initial velocity of the body will be equal to the velocity of balloon i.e. 1m/s in upward direction....and thus calculate...the answer will be 1 sec....0.1s in going up and 0.9s in coming down....

Profile image of vivek kumar
13 Years ago
1s
Profile image of SOURAV MISHRA
13 Years ago

the velocity of the released body is 1m/s upwards.

and its acceleration will be 10m/s2 downwards.

when released it was at a height of 4m from the ground.

so the equation is 5t2 - t - 4 = 0.

this gives t = 1s.

the body will take 1s to reach the ground.