Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a vertical u tube of uniform cross section contains mercury in both sides.a glycerine ( density 1.3 g/c.c) column of 10 cm is introduced into one arm.Oil of density 0.8 g/c.c is poured into the other arm until the oil and glycerine are in the same horizontal level; Find the length of oil column. density of mercury= 13.6g/c.c

a vertical u tube of uniform cross section contains mercury in both sides.a glycerine ( density 1.3 g/c.c) column of 10 cm is introduced into one arm.Oil of density 0.8 g/c.c is poured into the other arm until the oil and glycerine are in the same horizontal level; Find the length of oil column. density of mercury= 13.6g/c.c

Grade:

4 Answers

mohit yadav
54 Points
7 years ago
3.1
SOURAV MISHRA
37 Points
7 years ago

Let the length of the oil column be x cm. 

we can write

0.8*x*g + 13.6*(10 - x)*g = 1.3*10*g     where g is the acceleration due to gravity.

this gives x = 123/12.8 = 9.61 cm. 

the length of the oil column is 9.61 cm.

Koushik
22 Points
3 years ago
The glycerin and oil + some amount of mercury should be at   
some equipressure line.   
Let height of oil is h then
1.3 *g*10=0.8*g*x+13.6*g*(10-x)
Therefore, x =9.6 cm
Kushagra Madhukar
askIITians Faculty 629 Points
9 months ago
Dear student,
Please find the solution to your problem below.
 
Let the length of the oil column be x cm.
we can write
0.8*x*g + 13.6*(10 - x)*g = 1.3*10*g     [where g is the acceleration due to gravity]
This gives x = 123/12.8 = 9.61 cm
 
Thanks and regards,
Kushagra

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free