Mechanics

a vertical u tube of uniform cross section contains mercury in both sides.a glycerine ( density 1.3 g/c.c) column of 10 cm is introduced into one arm.Oil of density 0.8 g/c.c is poured into the other arm until the oil and glycerine are in the same horizontal level; Find the length of oil column. density of mercury= 13.6g/c.c

kling on

13 Years agoGrade

4 Answers

mohit yadav

13 Years ago

3.1

SOURAV MISHRA

13 Years ago

Let the length of the oil column be x cm.

we can write

0.8*x*g + 13.6*(10 - x)*g = 1.3*10*g where g is the acceleration due to gravity.

this gives x = 123/12.8 = 9.61 cm.

the length of the oil column is 9.61 cm.

Koushik

8 Years ago

The glycerin and oil + some amount of mercury should be at

some equipressure line.

Let height of oil is h then

1.3 *g*10=0.8*g*x+13.6*g*(10-x)

Therefore, x =9.6 cm

Kushagra Madhukar

6 Years ago

Dear student,

Please find the solution to your problem below.

Let the length of the oil column be x cm.

we can write

0.8*x*g + 13.6*(10 - x)*g = 1.3*10*g [where g is the acceleration due to gravity]

This gives x = 123/12.8 = 9.61 cm

Thanks and regards,

Kushagra

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kling on

4 Answers

mohit yadav

SOURAV MISHRA

Koushik

Kushagra Madhukar

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