A particle moves under force F(x)=(x^2-6x)N,where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation?

Question

Vikas TU · Answer

i think -6

Raghav Dua · Answer

You are right the answer is 6 N/m but how can i solve it.Please Explain.

AAYUSH KESHAVA · Answer

F(x)=x 2 -6x as x&asymp;0 ,x 2 &asymp;0 (as x 2 <<x) so neglegting second degree term of x in expression, we get F(x)=-6x on comparig with F(x)=-kx we get k=6 units

SOURAV MISHRA · Answer

for small displacements x 2 and other higher powers of x can be neglected in comparison to x. so F(x) = -6x approximately. therefore k = 6. so the force constant in shm is 6 N/m. please approve.

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A particle moves under force F(x)=(x^2-6x)N,where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation?

A particle moves under force F(x)=(x^2-6x)N,where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation?

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