a particle is projected at an initial velocity u with a angle of 60 with the vertical. The time after which the velocity vector becomes perpendicular to the initial velocity vector?
final angle of velocity vector is 30 with horizontal
show their horizontal components of velocity same and by vertical motion calc time
When a projectile makes 600 it makes an angle 300 with the horizontal.the velocity vector of the partical initially is v0=ucos30i+usin30j, after a time t the velocity vector is v=ucos30i+(usin30-gt)j the two vectors are perpendicular so their dot product is zero. we get that ucos30xucos30+usin30xusin30=gtsin30u=>u2=gtsin30=>t=u/gsin30
(ucos30°i + (usin30° - gt)j).(ucos30°i + usin30°j) = 0
u2 = ugtsin30°
t = 2u/g.
this is the time after which the velocity of the particle becomes perpendicular to the initial velocity vector.
Three identical balls are placed on a frictionless
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radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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