Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
a particle is projected at an initial velocity u with a angle of 60 with the vertical. The time after which the velocity vector becomes perpendicular to the initial velocity vector?
final angle of velocity vector is 30 with horizontal
show their horizontal components of velocity same and by vertical motion calc time
When a projectile makes 600 it makes an angle 300 with the horizontal.the velocity vector of the partical initially is v0=ucos30i+usin30j, after a time t the velocity vector is v=ucos30i+(usin30-gt)j the two vectors are perpendicular so their dot product is zero. we get that ucos30xucos30+usin30xusin30=gtsin30u=>u2=gtsin30=>t=u/gsin30
(ucos30°i + (usin30° - gt)j).(ucos30°i + usin30°j) = 0
u2 = ugtsin30°
t = 2u/g.
this is the time after which the velocity of the particle becomes perpendicular to the initial velocity vector.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !