Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A child standing at one end of a long trolley moving with speed v on a smooth horizontal track. If the child starts running towards the other end of the trolley with a speed u the centre of mass of the system will at a speed of what?

A child standing at one end of a long trolley moving with speed v on a smooth horizontal track. If the child starts running towards the other end of the trolley with a speed u the centre of mass of the system will at a speed of what?

Grade:12

4 Answers

harihara kumar
45 Points
8 years ago

v+((u/length ofthe trolley)+1)

Chetan Mandayam Nayakar
312 Points
8 years ago

mass of trolley=M,mass of child=m

answer=(Mv-mu)/(M+m)

Akash Kumar Dutta
98 Points
8 years ago

the child runs opposite to the direction of trolley or at the same direction ?
i

Rajendra Sharma
20 Points
8 years ago

the centre of mass will be going with speed v as no external effect or force is acting on the system and momentum will remain conserved. initial speed of trolley = v and hence final speed will be = v.

the friction due to the foot of the child act in equal and opposite pairs on the system and hence no effect is produced in the momentum. we are considering trolley and child together as a system.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free