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a particle moves from a point r1 =(2m)i+(3m)j to another point r2 = (3m)i +(2m)j during which a certain force F=(5N)i+(5N)j acts on it .find the work done by the force on the particle during the displacement.
Work done depends upon path taken,
There are two possible paths
1) (2)i
the work done is 0
w=f.(r2-r1)=0
displacement=S=r2-r1=(m)i - (m)jWD=F.S= (5m)i - (5m)j|WD|= root(50m^2)=5mroot2 ANS
answer=(5Ni+5Nj)·(r2-r1)
work done is zero.net displacement =i-j.
and work=f.ds net work=5-5=0.
the displacement of the particle is r2 - r1 = i - j.
therefore the work done is F.(r2 - r1) = 0 J.
so the work done is zero.
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