A CYCLIST RIDING WITH ASPEED OF 27 KMPH . AS HE APPROACHES A CIRCULAR TURN ON THE ROAD HE APPLIES BRAKES AND REDUCES HIS SPEED AT CONSTANT RATE OF 0.5 M/S^2,IF RAIUS OF CIRCLE IS 80 M. WHAT IS THE MAGNITUDE AND DIRECTION OF NET ACCELARATIOON.
SAURABH KUMAR , 11 Years ago
Grade 11
2 Answers
Akash Kumar Dutta
Last Activity: 11 Years ago
magnitude of tangential acc=.5 m/s^2 magnitude of centripetal acc.= v^2/r=45/64 m/s^2 then find mag. of net acc as root( tang. acc^2 + centripetal acc. ^2 ) and direction as tan inverse ( 32/45) with the radius of the circle.
KS
Last Activity: 11 Years ago
You must consider both , Centripetal and tangential Accelerations and for the final answer take the resultant of them.
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