two bodies of mass 1 kg and 2 kg move towards each other in mutually perpendicular direction with velocities 3m/s and 2 m/s respectively. If the bodies stick together after collision the heat liberated will be ? I.need the process of doing
Shuvam Shukla , 11 Years ago
Grade 12
5 Answers
Akash Kumar Dutta
Last Activity: 11 Years ago
Dear Shuvam, total momentum before collision=7 units. after collision M=3 so v=7/3 units, final energy=1/2Mv^2=49/6 J initial energy= 1/2m1(v1)^2 + 1/2 m2.(v2)^2 = 9/2+4=17/2 J Loss in energy= initial - final=17/2 - 49/6=2/6=1/3= .33 Joules(ANS)
Regards.
tejas naresh patel
Last Activity: 11 Years ago
60
Shuvam Shukla
Last Activity: 11 Years ago
Ans is 13/3...
Ansh Mahapatra
Last Activity: 6 Years ago
By law of conservation of momentum,
1*3+2*2=3*v
We get,v=7/3 m/s
Initial energy=17/2 J
Final energy=49/6 J
Energy lost as heat=1/3 J=0.33 J
Aditya
Last Activity: 5 Years ago
Answer is 13/3 because if we conserve momentum and subtract it we get the answer.
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free