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a particle starts falling from top of tower at t=0 simultaneously a car situated on ground some distance away starts moving towards the tower at a constant velocity of 5m/s the radius of curvature of the trajectory of particle as seen by observer in the jeep at some time t is 5/2*(17)3/2 metre ...FIND the time t in seconds.!!

a particle starts falling from top of tower at t=0 simultaneously a car situated on ground some distance away starts moving towards the tower at a constant velocity of 5m/s the radius of curvature of the trajectory of particle as seen by observer in the jeep at some time t is 5/2*(17)3/2 metre ...FIND the time t in seconds.!!

Grade:12

1 Answers

Akash Kumar Dutta
98 Points
9 years ago

Dear Prakhar,
the speed of the particle is= (-gt). j^
speed of car= (-5). i^
Relative velocity of the car= (-5).i^  +  (gt).j^
relative acc for car= (g).j^
but v^2/R=g
Find mod v and by
putiing putting the value of value of v and R we get the ans.
sorry I didnt proceeded since i didnt understood the value of R.
Regards.

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