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Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = MV is imparted to the body at one of its ends, what would be its angular velocity? impulse (a) V/L (b) 2V/L (c) V/3L (d) V/4L

shubhayan debnath , 12 Years ago
Grade 12
anser 7 Answers
mohit yadav

the ans is V/3L.

Last Activity: 12 Years ago
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Last Activity: 12 Years ago
Jilvin Jacob

The answer is V/L.

We know V=Rw, where V is the linear velocity, R is radius, w is angular velocity.

Given, 2 equal masses are held at the ends. Also, Impulse,F= MV.

ie the velocity of action is V.

Therefore, by question

V=Lw

or w=V/L

Hope you understood!

Last Activity: 12 Years ago
mohit yadav

 the ans is V/L

Last Activity: 12 Years ago
vivek kumar
  1. a
Last Activity: 12 Years ago
Austin
OPTION NO: A because
w=j1/2
2m*(1/2)^2=mv*1/2
w=v/l
 
THIS HAVE BEEN DONE !!
BECAUSE THE COMPUTER HAVE TO HAVE 100 CHAR
Last Activity: 9 Years ago
akshitdavps
Iw=MvL
w=MvL/I
I=ML*L
w=MvL/ML*L
    =v/L
w=v/L
As one mass is given the force itself and it is at one 
end its moment of inertia is zero.
The axis of rotation passes through the other end of the rod.
 
Last Activity: 6 Years ago
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