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Grade 12Mechanics

Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = MV is imparted to the body at one of its ends, what would be its angular velocity? impulse (a) V/L (b) 2V/L (c) V/3L (d) V/4L

Profile image of shubhayan debnath
13 Years agoGrade 12
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7 Answers

Profile image of mohit yadav
13 Years ago

the ans is V/3L.

Profile image of SRAJAN GUPTA
13 Years ago

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Profile image of Jilvin Jacob
13 Years ago

The answer is V/L.

We know V=Rw, where V is the linear velocity, R is radius, w is angular velocity.

Given, 2 equal masses are held at the ends. Also, Impulse,F= MV.

ie the velocity of action is V.

Therefore, by question

V=Lw

or w=V/L

Hope you understood!

Profile image of mohit yadav
13 Years ago

 the ans is V/L

Profile image of vivek kumar
13 Years ago
  1. a
Profile image of Austin
9 Years ago
OPTION NO: A because
w=j1/2
2m*(1/2)^2=mv*1/2
w=v/l
 
THIS HAVE BEEN DONE !!
BECAUSE THE COMPUTER HAVE TO HAVE 100 CHAR
Profile image of akshitdavps
6 Years ago
Iw=MvL
w=MvL/I
I=ML*L
w=MvL/ML*L
    =v/L
w=v/L
As one mass is given the force itself and it is at one 
end its moment of inertia is zero.
The axis of rotation passes through the other end of the rod.