# Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = MV is imparted to the body at one of its ends, what would be its angular velocity? impulse (a) V/L (b) 2V/L (c) V/3L (d) V/4L

54 Points
9 years ago

the ans is V/3L.

SRAJAN GUPTA
18 Points
9 years ago

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Jilvin Jacob
4 Points
9 years ago

The answer is V/L.

We know V=Rw, where V is the linear velocity, R is radius, w is angular velocity.

Given, 2 equal masses are held at the ends. Also, Impulse,F= MV.

ie the velocity of action is V.

Therefore, by question

V=Lw

or w=V/L

Hope you understood!

54 Points
9 years ago

the ans is V/L

vivek kumar
57 Points
9 years ago
1. a
Austin
11 Points
5 years ago
OPTION NO: A because
w=j1/2
2m*(1/2)^2=mv*1/2
w=v/l

THIS HAVE BEEN DONE !!
BECAUSE THE COMPUTER HAVE TO HAVE 100 CHAR
akshitdavps
7 Points
2 years ago
Iw=MvL
w=MvL/I
I=ML*L
w=MvL/ML*L
=v/L
w=v/L
As one mass is given the force itself and it is at one
end its moment of inertia is zero.
The axis of rotation passes through the other end of the rod.