Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A particle starts from the origin of co-ordinates at time t=0 and moves in the xy plane with a constant acceleration k in the y-axis direction.Its equation of motion is y^2=px^2,where p is a constant.Then,its velocity component in the x-direction is: A)variable B)underroot(2k/p) C)k/2p D)underroot(k/2p) ANS:D

A particle starts from the origin of co-ordinates at time t=0 and moves in the xy plane with a constant acceleration k in the y-axis direction.Its equation of motion is y^2=px^2,where p is a constant.Then,its velocity component in the x-direction is:


A)variable


B)underroot(2k/p)


C)k/2p


D)underroot(k/2p)


ANS:D

Grade:12th Pass

4 Answers

Akash Kumar Dutta
98 Points
8 years ago

Dear Sameer,
we know by eq. of trajectory=>
y=xtan(o) - x^2tan(o)/R
...Where R=range and (o)=angle of projection.....also here g=k
squaring both sides and comparing with the given eq.
We get ucos(o)=root(k/2p)ANS.

Regards.

mohit yadav
54 Points
8 years ago

the velocity component in x direction is variable not constant

SRAJAN GUPTA
18 Points
8 years ago

JOIN TAJENDER SINGH''S SPECIAL CLASSES WHICH GUARANTEE AIR B/W 1 TO 50!!!!! BELIEVE ME TAJINDER SINGH SIR IS LIKE GOD. BEFORE YOU CAN COMPLETE YOUR QUES, HE GIVES THE ANSWER AND ALSO OFFERS  SAMOSAS TO EAT AND JUICE TO DRINK. I AM HIS STUDENT AND IT HELPED ME IMMENSELY!!!!!!!!! I GOT AIR 15 IN IITJEE 2006.

Abhishekh kumar sharma
34 Points
8 years ago

from the equation we can get the angle of projection or the tan of angle which will give cos Q

then the x component of velocity will be k/2p^1/2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free