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A gun of mass 'M' fires a bullet of mass 'm' with a velocity 'v' relative to the gun. The average force required to bring the gun to rest in 0.5 seconds is
Dear ramya
conservation of linear momentum
let the velocity of gun is V1 wrt earth
so velocity of bullet wrt eart is v-V1
m(v-v1) =Mv1
v1=mv/(m+M)
now distance travel by gun in 0.5 sec
0=v1-a*0.5
a= 2v1 wher a is retardation of gun
so S= v1 *0.5 -1/2 *a *(0.5)2
=v1 /4
now from work energy theorem total work done is equal to change in kinetic energy
F.S =1/2 M *v12 -0
F.v1 /4 = 1/2 M *v12
F=2Mv1
=2Mmv/(m+M)
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