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`        A wedge shaped block 'A' of mass 'M' is at rest on a smooth horizontal surface.A small block 'B' of mass  'm' placed at the top edge of inclined plane of length 'L' as shown in the figure.By the time, the block 'B' reaches the bottom end the wedge 'A' will move a distance of  `
8 years ago

147 Points
```										Dear ramya
Since there is no external force in horizontal direction in wedge + mass system
so center of mass of wedge + mass syaytem will not move

let x1 is the COM of wedge from origin
and x is the distance moved by wedge
(Mx1 +mLcosΘ)/(m+M)   =  {M(x1+x) + mx}/(m+M)
x=mLcos Θ/(m+M)

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8 years ago
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