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A small bucket of mass M kg is attached to a long inextensible cord of length L m. The bucket is released when the cord is in horizontal position. At its lowest point the bucket scoops up m kg of water and swings.up to a height h. The height h is??

A small bucket of mass M kg is attached to a long inextensible cord of length L m. The bucket is released when the cord is in horizontal position. At its lowest point the bucket scoops up m kg of water and swings.up to a height h. The height h is??

Grade:12

2 Answers

Akash Kumar Dutta
98 Points
8 years ago

Dear Shuvam,

Velocity before scooping=root(2gL)
Applying conservation of momentum,
new velocity= (M/M+m).root(2gL)
the bucket stops when velocity = 0
=>u^2=2gh
=>2gh= [ (M/M+m)^2 ]. 2gL
=> h= [ (M/M+m)^2 ].L         (ANS)

Regards.

ruhi
16 Points
2 years ago
at the lowest position v=root 2gL
now, by using law of conservation of momentum
MV-(M+m)V'=0
Mv=(M+m)V'
V'=(M/M+m)root2gL
 
h=V'2/2g = (M/M+m)2L

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