Last Activity: 12 Years ago
Dear Nimish,
let the % be x,
Then by applying Boyles Law, we get,
P1V1=P2V2
=> P.V=(P+x.P).(V-V/10)
=> P.V=P(1+x).V.9/10
=> 10/9=1+x
=> x=1/9 % (ANS)
Regards.
Last Activity: 12 Years ago
here
P1V1/T1=P2V2/T2
BUT TEMP. REMAINS CONSTANT.
SO P1V1=P2V2
OR P1V1=P2(V1-V1/10)
OR P1V1=P2*9V1/10
OR P1=9P2/10
OR P2=10P1/9
NOW, PERCENTAGE INCREASE=(P2-P1)*100/P1
WHICH IS EQUAL TO 100/9%
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