Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
a tank is filled up to a height 2H WITH A LIQUID and is placed on a platform of height H from the ground .the distance x from the ground where a small hole is punched to get maximum range R is?
(squareroot of 24)H
The pressure of liquid is maximum at the bottom of the liquid in the tank.
So to get the maximum range, the hole must be pierced at the bottom of the tank, i.e.,
the required height x must be equal to H.
with regards,
Rishabh class xii
the value of x= 3h/2
since v=√2gh and in questiion h=3h-x
and range r=vt (projectile)
so r= [√2g(3h-x)][√2x/g]
simplifying
we have r is maximum if (3h-x).x is maximum
which is maximum at x=3h/2
its the same question asked just before.
ans is x=3H/2.
3H/2
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !