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a tank is filled up to a height 2H WITH A LIQUID and is placed on a platform of height H from the ground .the distance x from the ground where a small hole is punched to get maximum range R is?

anwesha mohanty , 12 Years ago
Grade 12
anser 6 Answers
abhinav anand

(squareroot of 24)H

Last Activity: 12 Years ago
Rishabh Maggirwar

The pressure of liquid is maximum at the bottom of the liquid in the tank.

So to get the maximum range, the hole must be pierced at the bottom of the tank, i.e., 

the required  height x must be equal to H.

 

with regards, 

Rishabh class xii

Last Activity: 12 Years ago
Abhishekh kumar sharma

the value of x= 3h/2

since v=√2gh   and in questiion h=3h-x

and range r=vt (projectile)

so    r= [√2g(3h-x)][√2x/g]

simplifying

we have r is maximum if (3h-x).x is maximum

which is maximum at x=3h/2

Last Activity: 12 Years ago
Akash Kumar Dutta

its the same question asked just before.

ans is x=3H/2.

Last Activity: 12 Years ago
gauhar singh

3H/2

Last Activity: 12 Years ago
DEV MUKHERJEE
let x be the distance fom the grond then here we have a horizontal projectlie time to come to grond =1/2 gt^2=x forwrd velocity =sqrt(2g(3h-x)) range=time *velocity; range =3h/2 (we would get a function for range which can be maximised using maxima and minima dr/dx=0 )
Last Activity: 12 Years ago
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