a tank is filled up to a height 2H WITH A LIQUID and is placed on a platform of height H from the ground .the distance x from the ground where a small hole is punched to get maximum range R is?
(squareroot of 24)H
The pressure of liquid is maximum at the bottom of the liquid in the tank.
So to get the maximum range, the hole must be pierced at the bottom of the tank, i.e.,
the required height x must be equal to H.
with regards,
Rishabh class xii
the value of x= 3h/2
since v=√2gh and in questiion h=3h-x
and range r=vt (projectile)
so r= [√2g(3h-x)][√2x/g]
simplifying
we have r is maximum if (3h-x).x is maximum
which is maximum at x=3h/2
its the same question asked just before.
ans is x=3H/2.
3H/2
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