Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

equation s(in Tth second)=u+at-a/2 seems to be dimensionally incorrect.why?

equation s(in Tth second)=u+at-a/2 seems to be dimensionally incorrect.why?

Grade:11

5 Answers

Akash Kumar Dutta
98 Points
8 years ago

we know s=ut + 1/2.a.t^2

putting t=1

s=u + 1/2.a.............(1)

THIS EQ. IS ALSO DIMENSIONALLY INCORRECT,according to your question.

buts its not so

the eq. s(at Tth sec.)=S(t) - s(t-1)

                              = u + at -a/2

hence we see that the value of time =(t) and (t-1) has already been put.as a result it appears that the dimensions

incorrect.its the same case as of eq.(1).

IT DOES NOT VIOLATE THE DIMENSIONAL CONCEPT.

Abhishekh kumar sharma
34 Points
8 years ago

the above question is

s=distance but

acoording to question the aboveequation has a unit m/sec which is independently added so we can

say it is dimensionall wrong

siddharth chandil
36 Points
8 years ago

u+at-a/2

u=a(t-1/2) how can it be correct t-1/2 isn''t possible becz time -constant term is dimensinally wrong

A. Srikar
20 Points
8 years ago

s=u+a(t-1/2)  is the correct formula..

 

JAYANT ARORA
37 Points
8 years ago

 Yes , this is a dimensionally incorrect formula but it is derived for our help and it do violates the law of dimensions ... but we need to accept this as it is ... bcoz this helps us in problems...

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free