Mechanics> circular-motion...
A point moves along a circle having a radius 20 cm with a constant tangential acceleration
5 cm/s2. How much time is needed after motion begins for the normal acceleration of the point to be
equal to tangential acceleration ?
3 Answers2 SECONDS
so,
V2/R=5
AND R=20cm
so V=10cm/s
and acceleration is dV/dt
5=dv/dt
integrating we get time is 2seconds
v^2/r=5 (since normal acc=v^2/r=tangential acc.=dv/dt=5)
v^2=5.r=5.20=100.
v=10 cm/s
but dv/dt=5
dv=5dt
v=5t
10=5t
t=2 secs.(ANS)
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