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given velocity v=40 root 2
v=u+at where a=g
1.v=u+at====>
we have to get the value by using this formula
2.s=ut+1/2gt^2 by using this formula wehave to get the value of displacements
thanks for asking these questions sorry idon''t have sufficient time to write the solution that''s why i wrote only formula what i know for that problem....
By using v=u+at we can find velocity at 2sec by taking a=g=-10m/s^2(a is negative because body moving upward but g acts in down ward direction)
v=40sqrt2-10*2=36.56m/sec.
b)Displacement can be find by using formula s=ut+(1/2)at^2 taking a=-10(same region explain above)
s=40sqrt2*2-(1/2)*10*4=93.13meters
velocity
v=u+at
a=-g
v=40√2-10*2
v=20(2√2-1)m/s
s=ut+at2/2
s=40√2*2-10*2*2
s=80√2-40
s=40(2√2-1)m
Question is hard
.v=u+at
what is the angle??????
without it how can u calculate the components of velocityy
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