A particle of mass "m" is at x=0 with velocity v=u in the x-direction at t=0.It is subjected to a friction force -bv,where b is a positive constant.The position of the particle at "t" tends to infinity is ?
Options are - 1)mu/b
2)u/mb
3)2mu/b
4)mu/2b

Question

Chetan Mandayam Nayakar · Answer

m*dv/dt=-bv you can very easily solve the above equation to find v(t) x(t)=&int;v(t) dt

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A particle of mass "m" is at x=0 with velocity v=u in the x-direction at t=0.It is subjected to a friction force -bv,where b is a positive constant.The position of the particle at "t" tends to infinity is ? Options are - 1)mu/b 2)u/mb 3)2mu/b 4)mu/2b

A particle of mass "m" is at x=0 with velocity v=u in the x-direction at t=0.It is subjected to a friction force -bv,where b is a positive constant.The position of the particle at "t" tends to infinity is ?
Options are - 1)mu/b
2)u/mb
3)2mu/b
4)mu/2b

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A particle of mass "m" is at x=0 with velocity v=u in the x-direction at t=0.It is subjected to a friction force -bv,where b is a positive constant.The position of the particle at "t" tends to infinity is ? Options are - 1)mu/b 2)u/mb 3)2mu/b 4)mu/2b

A particle of mass "m" is at x=0 with velocity v=u in the x-direction at t=0.It is subjected to a friction force -bv,where b is a positive constant.The position of the particle at "t" tends to infinity is ? Options are - 1)mu/b 2)u/mb 3)2mu/b 4)mu/2b

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A particle of mass "m" is at x=0 with velocity v=u in the x-direction at t=0.It is subjected to a friction force -bv,where b is a positive constant.The position of the particle at "t" tends to infinity is ?
Options are - 1)mu/b
2)u/mb
3)2mu/b
4)mu/2b