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The kinetic energy of a particle executing shm is 16 j when it is in its mean position If the amplitude of oscillation is 25 and the mass of particle is 5.12kg the time period of its oscillation is

pallavi pradeep bhardwaj , 15 Years ago

Grade 12

3 Answers

Badiuddin askIITians.ismu Expert

Last Activity: 15 Years ago

Dear Pallavi

x=Xsinwt

v=dx/dt =Xwcoswt

at mean position particle has only kinetic energy

at mean position velocity is V=Xw

K.E=1/2 *m*V²

16= 1/2 m X²w²

32=5.12 (25)² (2∏/T)²

now you can calculate T

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Badiuddin

shanky shanky

Last Activity: 15 Years ago

i am agree with previous sol.

so ans.=52.34sec

ts tabse n

Last Activity: 6 Years ago

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