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The kinetic energy of a particle executing shm is 16 j when it is in its mean position If the amplitude of oscillation is 25 and the mass of particle is 5.12kg the time period of its oscillation is

pallavi pradeep bhardwaj , 16 Years ago
Grade 12
anser 3 Answers
Badiuddin askIITians.ismu Expert

Dear Pallavi

x=Xsinwt

v=dx/dt =Xwcoswt

at mean position particle has only kinetic energy

at mean position velocity is V=Xw

K.E=1/2 *m*V2

  16= 1/2 m X2w2

 32=5.12 (25)2 (2∏/T)2

now you can calculate T


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Badiuddin

Last Activity: 16 Years ago
shanky shanky

i am agree with previous  sol.

so ans.=52.34sec

Last Activity: 16 Years ago
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