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The length of the second pendulum on the surface of earth is 1 m The length of seconds pendulum on the surface of moon where g is 1/6th value of g on the surface of earth

pallavi pradeep bhardwaj , 16 Years ago

Grade 12

2 Answers

Rohith Gandhi

Dear Pallavi,

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Rohith Gandhi P

Last Activity: 16 Years ago

Kushagra Madhukar

Dear student,

Please find the solution to your problem.

Tm = 2π√L/(g/6)

Hence, 2 = 2π√L/(g/6)

or, L = g/6π²

or, L = 0.167 m

Thanks and regards,

Kushagra

Last Activity: 5 Years ago

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