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The motion of the particle executing shm is given by x=0.01sin100pi(t+.05) where x in metres and time is in seconds The time period is

pallavi pradeep bhardwaj , 16 Years ago
Grade 12
anser 1 Answers
Rohith Gandhi

Dear Pallavi,

x = 0.01sin(100pi*t + 5*pi) => x =  -0.01sin(100*pi*t)

 

hence from equation, omega = angular frequency = 100*pi = 2*pi/T

 

=>Time period ,  T = 2/100 = 0.02 seconds


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Rohith Gandhi P

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