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A simple pendulum is suspended from the ceiling of a car accelerating uniformly on a horizontal road.If the acceleration is a and length of the pendulum is l,find the time period of small oscillation about the mean position.

Chetan Mandayam Nayakar
312 Points
8 years ago

T=2pi√(l/(√(a2+g2)))

Yogita Bang
39 Points
8 years ago

The car is accelerating in horizontal direction with acceleration a. The accleration due to gravity is g in downward direction.

Resultant acceleration a'' = (a2 + g2)1/2

Time period T=2pi(L/a'')1/2 =2pi{L/(a2+g2)1/2}

one year ago
Dear student,

The car is accelerating in horizontal direction with acceleration a. The accleration due to gravity is g in downward direction.
Resultant acceleration a'' = (a2 + g2)
Time period T = 2π(L/a'') = 2π{L/(a2+g2)}

Thanks and regards,
Kushagra