A simple pendulum is suspended from the ceiling of a car accelerating uniformly on a horizontal road.If the acceleration is a and length of the pendulum is l,find the time period of small oscillation about the mean position.

Question

Chetan Mandayam Nayakar · Answer

T=2pi&radic;(l/(&radic;(a 2 +g 2 )))

Yogita Bang · Answer

The car is accelerating in horizontal direction with acceleration a. The accleration due to gravity is g in downward direction.

Resultant acceleration a'' = (a² + g²)^1/2

Time period T=2pi(L/a'')^1/2=2pi{L/(a²+g²)^1/2}

Kushagra Madhukar · Answer

Dear student, Please find the solution to your problem. The car is accelerating in horizontal direction with acceleration a. The accleration due to gravity is g in downward direction. Resultant acceleration a'' = √ (a 2 + g 2 ) Time period T = 2 π √ (L/a'') = 2 π √ {L/ √ (a 2 +g 2 )} Thanks and regards, Kushagra

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A simple pendulum is suspended from the ceiling of a car accelerating uniformly on a horizontal road.If the acceleration is a and length of the pendulum is l,find the time period of small oscillation about the mean position.

A simple pendulum is suspended from the ceiling of a car accelerating uniformly on a horizontal road.If the acceleration is a and length of the pendulum is l,find the time period of small oscillation about the mean position.

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