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A uniform chain of mass m and length l overhangs a table with its two thirds part on the table. Find the work done by a person to put the hanging part back on the table.

Naina Razdan , 15 Years ago
Grade 12
anser 1 Answers
Badiuddin askIITians.ismu Expert

Last Activity: 15 Years ago

Dear Eshita

 

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mass of the hanging portion =(m/l) *l/3

                                         =m/3


center of mass of the hanging portion from the top of the tabel  = l/6


work done = increse in potential energy =(m/3) *g * (l/6)

                                                         =mgl/18


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