Badiuddin askIITians.ismu Expert
Last Activity: 15 Years ago
Dear Eshita
mass of the hanging portion =(m/l) *l/3
=m/3
center of mass of the hanging portion from the top of the tabel = l/6
work done = increse in potential energy =(m/3) *g * (l/6)
=mgl/18
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best.
Regards,
Askiitians Experts
Badiuddin