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Grade Upto college levelMechanics

30. A fly traveling horizontally at a constant speed enters the open window of a train and leaves through the opposite window 3 m away 0.75 s later. If the fly travels perpendicular to the trains motion as seen from an observer on the ground, and the train is traveling at 3 m/s, determine the speed of the fly as observed by a passenger on the train

Profile image of yours katarnak Suresh
13 Years agoGrade Upto college level
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Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer11 Months ago

To find the speed of the fly as observed by a passenger on the train, we need to analyze the situation using some basic principles of relative motion. The fly is moving perpendicular to the train's motion, and we can break down the problem into components to find the speed relative to the train.

Understanding the Scenario

We have a train moving at a speed of 3 m/s. The fly enters the train through one window and exits through the opposite window, which is 3 meters away, in 0.75 seconds. Since the fly's motion is perpendicular to the train's direction, we can treat its speed and the train's speed as two components of a right triangle.

Calculating the Fly's Speed

First, we can calculate the speed of the fly relative to the ground. The distance traveled by the fly is 3 meters, and the time taken is 0.75 seconds. We can use the formula for speed:

  • Speed = Distance / Time

Plugging in the values:

  • Speed of the fly = 3 m / 0.75 s = 4 m/s

Relative Motion Analysis

Now, we need to find the speed of the fly as observed by a passenger on the train. Since the fly is moving perpendicular to the train's direction, we can use the Pythagorean theorem to find the resultant speed of the fly relative to the train.

  • Let Vfly be the speed of the fly (4 m/s).
  • Let Vtrain be the speed of the train (3 m/s).

The resultant speed Vresultant can be calculated as follows:

  • Vresultant = √(Vfly2 + Vtrain2)

Substituting the values:

  • Vresultant = √(42 + 32)
  • Vresultant = √(16 + 9) = √25 = 5 m/s

Final Thoughts

Thus, the speed of the fly as observed by a passenger on the train is 5 m/s. This example illustrates how relative motion can be analyzed using vector components and the Pythagorean theorem, which is a fundamental concept in physics. Understanding these principles helps in visualizing and solving problems involving different frames of reference.