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A train travels along a horizontal circular curve that has a radius of 200 m. If the speed of the train is uniformly increased from 30 km/h to 45 km/h in 5 s, determine the magnitude of the acceleration at the instant the speed of the train is 40 km/h.
a = aT + aR ----------->(vector addition)
Therefore, a2= aT2 + aR2 (since, angle between aT & aR is 90º)
aT= {45(5/18) - 30(5/18)}/5 = 5/6
aR= v2/r = {40(5/18)}/200 = 1/18
a2= 25/36 + 1/324 = 226/324
a≈ 0.835 m/s2
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