Question icon
Grade 12Mechanics

Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

Profile image of pallavi  pradeep bhardwaj
16 Years agoGrade 12
Answers icon

2 Answers

Profile image of Rohith  Gandhi
16 Years ago

Dear Pallavi,

 

5924-104_8202_pr6.jpeg

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.


All the best Pallavi!!!




Regards,

Askiitians Experts

Rohith Gandhi P

 

Profile image of Kushagra Madhukar
6 Years ago
Dear student,
Please find the attached solution to your problem below.
 
Maximum velocity for an oscillation, vmax = Aw
→ V1 = V2 (max.)
→ A1w1 = A2w2
→ A1/A2 = w2/w1
              = (√k2/m) / (√k1/m)
              = √(k2/k1)
 
Hope it helps.
Thanks and regards,
Kushagra