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Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

Grade:12

2 Answers

Rohith Gandhi
24 Points
12 years ago

Dear Pallavi,

 

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Kushagra Madhukar
askIITians Faculty 629 Points
2 years ago
Dear student,
Please find the attached solution to your problem below.
 
Maximum velocity for an oscillation, vmax = Aw
→ V1 = V2 (max.)
→ A1w1 = A2w2
→ A1/A2 = w2/w1
              = (√k2/m) / (√k1/m)
              = √(k2/k1)
 
Hope it helps.
Thanks and regards,
Kushagra

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