Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

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Rohith Gandhi · Answer

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Kushagra Madhukar · Answer

Dear student, Please find the attached solution to your problem below. Maximum velocity for an oscillation, v max = Aw → V 1 = V 2 (max.) → A 1 w 1 = A 2 w 2 → A 1 /A 2 = w 2 /w 1 = (√k 2 /m) / (√k 1 /m) = √(k 2 /k 1 ) Hope it helps. Thanks and regards, Kushagra

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Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

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Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

Two bodies M and N of equal masses are suspended from two seperate massless spring of force constant K1 and K2 respectively.If the two bodies osscilate vertically such that their maximum velocities are equal the ratio of the amplitude of M to that of N is

2 Answers

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