The period of osscilation of a simple pendulum of constant length at earth surface is T its period inside a mine is:

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Badiuddin askIITians.ismu Expert · Answer

Dear Pallavi T=2&prod; &radic;(l/g) since g decreses when we go inside the earth surface so T will increase Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards, Askiitians Experts Badiuddin

manni stubtza · Answer

slightly increase because inside mine value of g sligtly decrease

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The period of osscilation of a simple pendulum of constant length at earth surface is T its period inside a mine is:

The period of osscilation of a simple pendulum of constant length at earth surface is T its period inside a mine is:

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