A square of side 4 units is divided into four equal squares. the square portion ABCH is removed and placed over HCDE. What is the new centre of mass of the system. The orginal body thickness and density is uniform

Dear M.Sai

 

 

mass is not moved along the x axix so for new center of mass x co ordinate will remain same as earlier

and for y co ordinate of new center of mass

let mass of each part is m ,center of mass of each part of square  lies at their center

length of each side of small square is 2 unit

 

Y= [ m*1 +m*(-1) +m*(-1) +m*(-1)]/(m+m+m+m)

   =-1/2

so new center of mass (0,-1/2)

 

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