Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
M. Sai Suchandan Reddy Grade: 11

A square of side 4 units is divided into four equal squares. the square portion ABCH is removed and placed over HCDE. What is the new centre of mass of the system. The orginal body thickness and density is uniform

8 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points

Dear M.Sai




mass is not moved along the x axix so for new center of mass x co ordinate will remain same as earlier

and for y co ordinate of new center of mass

let mass of each part is m ,center of mass of each part of square  lies at their center

length of each side of small square is 2 unit


Y= [ m*1 +m*(-1) +m*(-1) +m*(-1)]/(m+m+m+m)


so new center of mass (0,-1/2)


Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
Askiitians Experts

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details