A square of side 4 units is divided into four equal squares. the square portion ABCH is removed and placed over HCDE. What is the new centre of mass of the system. The orginal body thickness and density is uniform
Dear M.Sai
mass is not moved along the x axix so for new center of mass x co ordinate will remain same as earlier
and for y co ordinate of new center of mass
let mass of each part is m ,center of mass of each part of square lies at their center
length of each side of small square is 2 unit
Y= [ m*1 +m*(-1) +m*(-1) +m*(-1)]/(m+m+m+m)
=-1/2
so new center of mass (0,-1/2)
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