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# 2 particles bearing mass in the ratio n:1 are interconnected by a light inextensible string that passes over a smooth pulley.If the system is released,then the acceleration of the centre of mass of the system is? please solve the above question with proper explaination.

sanatan sharma
26 Points
8 years ago

draw the fbd of the system , write eqn of motion and obtain the acceleration of the bodies

let us assumw it comes out as a

now acceleration of the centre of mass will be given by

= (m1a-m2a)/(m1+m2)

negative sign because of the oppositedly directed accn of the two bodies

somy chaturvedi
10 Points
8 years ago

ans is [n-1/n+1]^2*g in downwad direction. if im right then like it , i will give the solution

somy chaturvedi
10 Points
8 years ago

solution

find acc. of both the blocks and put those in     Acm=m1A1+m2aA2/m1+m2    with signs!!!!!!!!   [very important].

thanxxx