2 particles bearing mass in the ratio n:1 are interconnected by a light inextensible string that passes over a smooth pulley.If the system is released,then the acceleration of the centre of mass of the system is?
please solve the above question with proper explaination.

Question

sanatan sharma · Answer

draw the fbd of the system , write eqn of motion and obtain the acceleration of the bodies

let us assumw it comes out as a

now acceleration of the centre of mass will be given by

= (m₁a-m₂a)/(m₁+m₂)

negative sign because of the oppositedly directed accⁿof the two bodies

somy chaturvedi · Answer

ans is [n-1/n+1]^2*g in downwad direction. if im right then like it , i will give the solution

somy chaturvedi · Answer

solution find acc. of both the blocks and put those in Acm=m1A1+m2aA2/m1+m2 with signs!!!!!!!! [very important]. thanxxx

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2 particles bearing mass in the ratio n:1 are interconnected by a light inextensible string that passes over a smooth pulley.If the system is released,then the acceleration of the centre of mass of the system is? please solve the above question with proper explaination.

2 particles bearing mass in the ratio n:1 are interconnected by a light inextensible string that passes over a smooth pulley.If the system is released,then the acceleration of the centre of mass of the system is?
please solve the above question with proper explaination.

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