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two objects moving along the same straight line are leaving point A with an acceleration a,2a and velocity 2u,u respectively at time t=0 the distance moved by the object w.r.t point A when one object overtake the other is:
When one object will overtake the other, both of them will travel the same distance in the same time interval. Distance travelled by the first body in a time interval ''t''(say) ,will be, by the scond kinematic equation, d = 2ut+1/2at^2 Also, distance travelled by the second body will be d=ut+1/2*2at^2 Equating the two, we get 2ut+1/2at^2=ut+at^2 Solving, we get t=0 and t=2u/a d=2u*2u/a+1/2a*4u^2/a^2 d=6u^2/a
When one object will overtake the other, both of them will travel the same distance in the same time interval.
Distance travelled by the first body in a time interval ''t''(say) ,will be, by the scond kinematic equation,
d = 2ut+1/2at^2
Also, distance travelled by the second body will be
d=ut+1/2*2at^2
Equating the two, we get
2ut+1/2at^2=ut+at^2
Solving, we get t=0 and t=2u/a
d=2u*2u/a+1/2a*4u^2/a^2
d=6u^2/a
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