When one object will overtake the other, both of them will travel the same distance in the same time interval.
Distance travelled by the first body in a time interval ''t''(say) ,will be, by the scond kinematic equation,
d = 2ut+1/2at^2
Also, distance travelled by the second body will be
d=ut+1/2*2at^2
Equating the two, we get
2ut+1/2at^2=ut+at^2
Solving, we get t=0 and t=2u/a
d=2u*2u/a+1/2a*4u^2/a^2
d=6u^2/a
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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Last Activity: 9 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
