two objects moving along the same straight line are leaving point A with an acceleration a,2a and velocity 2u,u respectively at time t=0the distance moved by the object w.r.t point A when one object overtake the other is:

When one object will overtake the other, both of them will travel the same distance in the same time interval.

Distance travelled by the first body in a time interval ''t''(say) ,will be, by the scond kinematic equation,

d = 2ut+1/2at^2

Also, distance travelled by the second body will be

d=ut+1/2*2at^2

Equating the two, we get

2ut+1/2at^2=ut+at^2

Solving, we get t=0 and t=2u/a

d=2u*2u/a+1/2a*4u^2/a^2

d=6u^2/a