Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

An elevator car whose floor to ceiling distance is equal to 2.7m starts ascending with constant acceleration of 1.2m/s . Two sec after it starts; a bolt begins to fall from the ceiling of the elevator. Find (a) the bolts free fall time; (b) The displacement and the distance covered by the bolt during the fall w.r.t. ground.

An elevator car whose floor to ceiling distance is equal to 2.7m starts ascending with constant acceleration of 1.2m/s . Two sec after it starts; a bolt begins to fall from the ceiling of the elevator. Find 
(a) the bolts free fall time; 


(b) The displacement and the distance covered by the bolt during the fall w.r.t. ground. 

Grade:

2 Answers

md salik
31 Points
9 years ago

s=ut+1/2 at2

2.7=1/2(g+a)*t2

2.7=11/2*t2

11 t2=5.4

approx-

t2=0.5

t=2.2 sec

Satyam Mahato
4 Points
9 years ago

part 1 is correct.

But what is the answer of 2nd part.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free