Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a 70 kg man leans against a hollow cylindrical wall with radius 3m.coefficient of friction between clothing and wall is 0.15.find minimum speed of rotation of cylinder so that the man doesnt fall when the floor is removed?

a 70 kg man leans against a hollow cylindrical wall with radius 3m.coefficient of friction between clothing and wall is 0.15.find minimum speed of rotation of cylinder so that the man doesnt fall when the floor is removed?

Grade:

3 Answers

rupali sehgal
19 Points
8 years ago

Taking the man to be the system,

Normal force supplies the necessary centripetal force.

therefore, N=mv2/R

Also, to ensure that the person does not fall, frictional force should be equal to the person''s weight.

therefore, F= mg

=> µs.N=mg

from (1)

µs.mv2/R=mg

µs(Rω)2/R=g                 {v=Rω}

(0.15)(3)(ω)2 =10

ω2= 10/0.45= 22.22

ω = 4.71 rad/sec2

 

Hope it helps. Do approve if satisfied by the answer!

All the best!

pk bose
4 Points
8 years ago

thanx a lot !! helped me a lot ! thank u!

rupali sehgal
19 Points
8 years ago

Your welcome!

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free