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Grade:

                        

a 70 kg man leans against a hollow cylindrical wall with radius 3m.coefficient of friction between clothing and wall is 0.15.find minimum speed of rotation of cylinder so that the man doesnt fall when the floor is removed?

7 years ago

Answers : (3)

rupali sehgal
19 Points
							

Taking the man to be the system,

Normal force supplies the necessary centripetal force.

therefore, N=mv2/R

Also, to ensure that the person does not fall, frictional force should be equal to the person''s weight.

therefore, F= mg

=> µs.N=mg

from (1)

µs.mv2/R=mg

µs(Rω)2/R=g                 {v=Rω}

(0.15)(3)(ω)2 =10

ω2= 10/0.45= 22.22

ω = 4.71 rad/sec2

 

Hope it helps. Do approve if satisfied by the answer!

All the best!

7 years ago
pk bose
4 Points
							

thanx a lot !! helped me a lot ! thank u!

7 years ago
rupali sehgal
19 Points
							

Your welcome!

7 years ago
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