A particle after starting from rest , experiences , constant acceleration for 20 seconds. if it covers a distance of s1, in first 10 seconds and distance s2 in next 10 seconds. then,

s1=s2

ANSWER IS 3S₁=S₂

ANSWER WONT BE S₁=S₂ BECAUSE .....

     S₁=UT₁+1/2 * a * T₁²  .................  (U=0)(T₁=10)

      S₁   = 1/2 * a * 100...........................(1)

   NOW YOU CANT DO S₂ = UT₂+1/2 *a * T₂²  AND U=0   BECAUSE AT POINT ''B'' YOU WILL GET SOME VELOCITY ''V''

 BUT YOU CAN DO  S₂=(S₁+S₂)-S_{1   ................................(2)}

(S₁+S₂)= UT+1/2*a*T²  (U=0)(T=20)

(S₁+S₂)=1/2 *a*400......................(3)

 PUT (1) AND (3) IN (2)   YOU GET S₂=1/2 *a * 300..........................(4)

  ON COMPARING (1) AND (4)  WE GET 3S₁=S_{2.......................................ANSWER}

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