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Grade: 12

                        

Q1 The bob of a simple pendulum of length I is released from point P. What is the angle made by the net acceleration of the bob with the string at point Q.

8 years ago

Answers : (2)

Aman Bansal
592 Points
							

Dear Anurag,

A typical simple pendulum consists of a heavy pendulum bob (mass = M) suspended from a light string. It is generally assumed that the mass of the string is negligible. If the bob is pulled away from the vertical with some angle, q, and released so that the pendulum swings within a vertical plane, the period of the pendulum is given as:

 

T = 2(L/g)1/2(1 + 1/4 sin2q/2 + 9/16sin4q/2 + ...)            Equation 1

 

where L is the length of the pendulum and g is the acceleration due to earth''s gravity. Note only the first three terms in the infinite series is

given in the above equation. The period is defined as the time required for the pendulum to complete one oscillation. That is, if the pendulum is released at some point, P, the period is defined as the time required for the pendulum to swing along its path and return to point P.

 

The above formula for the pendulum''s period is greatly simplified if we limit the initial angle q to small values. If q is small, we can approximate the period of the pendulum with the following expression. 

      T = 2(L/g)1/2         Equation 2

 

Note that the period in this expression is independent of the pendulum''s mass as initial angle, q. It is important to understand that the above equation is valid only in the small angle approximationIf the magnitude of the displacement is sufficiently small, and if we neglet the effects of friction and air resistance, the motion of the mass is relatively simple and is called simple harmonic motion.

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Thanks

Aman Bansal

Askiitian Expert


8 years ago
Anurag Kshatri
36 Points
							

To,

Aman Sir

this question need to be solve by the principals of laws of motion or work, energy and power

8 years ago
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