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Grade: 12

                        

A Juggler tosses a ball up in the air initial speed u. At the instant it reaches its maximum height H, he tosses up a second ball with the same initial speed. In what height will two ball collide?

8 years ago

Answers : (1)

Deepak Sangle
13 Points
							For first ball,0 = u^2 -2gH  thus u^2 = 2gH ...... (1)after the ball collides at height h, for first ball H-h = 1/2 gt^2 .....(2)  and for second,h =ut - 1/2 gt^2  ......(3) from eqn (2) and (3) we get H = ut or H^2 = u^2 t^2 or H^2 = 2gHt^2  .... (from 1)  and thus gt^2 = H /2 Putting it in eqn (3) we get h = H  - 1/2 H/2 and thus h = 3H / 4
						
3 years ago
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