Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
The velocity-time graph of a moving object is given in the figure. Find the maximum acceleration of the body and distance travelled by the body in the interval of time in which this acceleration exists.
acceleration is equal to slope of v-t graph. so, acceleration is max when slope of graph is max.Therefore, acceleration is max. between 30s to 40s. distance travelled is given by the area under the graph between 30s and 40s.
hey harsh plz help me with da other questiion also...
we know a=dv/dt
so the acceleration will be maximum when slope is maximum
we see the graph has maximum slope between 30-40seconds
so acceleration is maximum at 30-40 seconds
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !