×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
The velocity-time graph of a moving object is given in the figure. Find the maximum acceleration of the body and distance travelled by the body in the interval of time in which this acceleration exists.

```
8 years ago

## Answers : (3)

Harsh Singh
11 Points
```							acceleration is equal to slope of v-t graph. so, acceleration is max when slope of graph is max.Therefore, acceleration is max. between 30s to 40s. distance travelled is given by the area under the graph between 30s and 40s.
```
8 years ago
ankit cool
15 Points
```							hey harsh plz help me with da other questiion also...
```
8 years ago
Rohan Das
36 Points
```							we know a=dv/dt
so the acceleration will be maximum when slope is maximum
we see the graph has maximum  slope between 30-40seconds
so acceleration is maximum at 30-40 seconds
```
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions