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The initial velocity of the parachutist is zero
now V=u+gt
V=0+(-10)10
V=-100 (-sign as the velocity is in downward direction)
Now S=ut+1/2ut^2
so S=0+1/2(-10)*100
S=500
Now H=2495-500
=1995
NOw v^2=u^2+2ah
v^2=10000-2*2.5*1995
v^2=25
v=5
so his velocity on reaching the ground is 5m/s
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