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A mass m is suspended from a wire. Change in length of the wire is dl. Now the same wire is stretched to double its length and the same mass is suspended from the wire. The change in length in this case will become :- a)dl b) 2dl c) 4dl d) 8dl
Let F = mg be the force L , A° , dlº and 2L , A , dl be the length , area , chenge in length before and efter stretching On stretching the wire the volume before and after will remain same Thus A°*L=A*2L ≡ A°=2A Now equating youngs modulus as material of wire remain same (F*L)/(A°*dl°) = (F*2L)/(A*dl) 2A°*dl° = A*dl 4dl° = dl
Let F = mg be the force
L , A° , dlº and 2L , A , dl be the length , area , chenge in length before and efter stretching
On stretching the wire the volume before and after will remain same
Thus A°*L=A*2L ≡ A°=2A
Now equating youngs modulus as material of wire remain same
(F*L)/(A°*dl°) = (F*2L)/(A*dl)
2A°*dl° = A*dl
4dl° = dl
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