Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Arnab Mandal Grade: 11

A mass m is suspended from a wire. Change in length of the wire is dl. Now the same wire is stretched to double its length and the same mass is suspended from the wire. The change in length in this case will become :-

a)dl          b) 2dl                     c) 4dl                     d) 8dl

5 years ago

Answers : (1)

Chirrag Nangia
32 Points

Let F = mg be the force

L , A° , dlº and 2L , A , dl be the length , area , chenge in length before and efter stretching

On stretching the wire the volume before and after will remain same

Thus A°*L=A*2L  ≡ A°=2A

Now equating youngs modulus as material of wire remain same

(F*L)/(A°*dl°) = (F*2L)/(A*dl)

2A°*dl° = A*dl

4dl° = dl

5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details