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A ball is projected with a velocity 20m/s at an angle to the horizontal. In order to have the maximum range, its velocity at the highest position should be??
For maximum range angle Ø=45 velocity at highest point = ucosØ = 20 cos45 = 10√2
For maximum range angle Ø=45
velocity at highest point = ucosØ
= 20 cos45
= 10√2
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