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A uniform rope lies on a table that parts of it lays over. The rope begins to slide when the length of the hanging part is 25% of entire length. The coffecient of friction between rope and table is
(a)0.33 (b)0.25 (c) 0.5 (d)0.2
Let m be mass per unit length and L be the length
force of friction on part kept on table = weight of hanging part
u*m*(3L/4)*g = m*(L/4)*g
u = 0.33
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