Aman Bansal
Last Activity: 12 Years ago
Dear Naman,
he blocks are connected by a taut string. Hence, their accelerations are same. Let us assume directions of accelerations as shown in the figure. Also, let the magnitude of accelerations be “a”.
Free body diagram of body of mass 10 kg
The external forces are (i) weight of block, 10g, and (ii) tension, T, in the string.
∑F y =T−10g=10a ⇒T−10x10=10a ⇒T=100+10a
Free body diagram of body of mass 20 kg
The external forces are (i) weight of block, 20g, and (ii) tension, T, in the string.
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Aman Bansal
Askiitian Expert