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When 2 pulleys are considered such that tension acting in 1st pulley is twice that of in the 2nd pulley , then why is the acceleration of the 1st pulley is half of that of 2nd pulley? T1= 2T2 a2=2a1

When 2 pulleys are considered such that tension acting in 1st pulley is twice that of in the 2nd pulley , then why is the acceleration of the 1st pulley is half of that of 2nd pulley?


              T1= 2T2


              a2=2a1


 

Grade:

1 Answers

Aman Bansal
592 Points
9 years ago

Dear Naman,

he blocks are connected by a taut string. Hence, their accelerations are same. Let us assume directions of accelerations as shown in the figure. Also, let the magnitude of accelerations be “a”.

 

Figure 2
Static pulley system
 Static pulley  system  (fap2.gif)

 

Free body diagram of body of mass 10 kg  

The external forces are (i) weight of block, 10g, and (ii) tension, T, in the string.

 

Figure 3
Free body diagram
 Free body diagram  (fap3.gif)

 

 

 
F y =T10g=10a T10x10=10a T=100+10a

 

Free body diagram of body of mass 20 kg

The external forces are (i) weight of block, 20g, and (ii) tension, T, in the string.

 

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