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When 2 pulleys are considered such that tension acting in 1st pulley is twice that of in the 2nd pulley , then why is the acceleration of the 1st pulley is half of that of 2nd pulley? T1= 2T2 a2=2a1


8 years ago

Aman Bansal
592 Points
							Dear Naman,
he blocks are connected by a taut string. Hence, their accelerations are same. Let us assume directions of accelerations as shown in the figure. Also, let the magnitude of accelerations be “a”.

Free body diagram of body of mass 10 kg
The external forces are (i) weight of block, 10g, and (ii) tension, T, in the string.

∑F y =T−10g=10a ⇒T−10x10=10a ⇒T=100+10a

Free body diagram of body of mass 20 kg
The external forces are (i) weight of block, 20g, and (ii) tension, T, in the string.

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Aman Bansal

8 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions