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Dear Pratiek
Try to solve the problem using relative velocity and newton equations
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TIME TAKEN BY ball to reach highest point-> 0=20-9.8t =>t=2.04s
dist. covered by ball to reach the highest point->0=400-19.6s =>s=20.4m
dist covered by lift in (2+2.04)s=4.08m
distance between ball at 4.04sfrom start of lift=20.4+12-4.08=28.32
let after t seconds from falling of ball ,it hits elevator
then dist. covered by ball in t seconds=28.32m -dist covered by lift in t sec
1/2gt^2=28.32m - (1/4)t^2
(4.9 + 0.25)t^2=28.32
5.15 t^2 =28.32
t=2.34s
so ball hits elevator at (2+2.04+2.32)=6.36s
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